Assume the price of an entry ticket, i.e., the price of 1 share, is always a unit $1$. The revenue from selling 1 share is immediately divided equally among all existing shareholders (including the new shareholder who just purchased this 1 share).
Participants have a unique ordinal identifier, which is their entry sequence number, $i \in \mathbb{N}^+$
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At some point in the future, the system develops to have more participants, with a total number of $n \in \mathbb{N}^+$. (The same person participating twice counts as 2 people.)
Then the cost for participant $i$ is $1$, and the revenue is
$$ R(i,n)=\sum_{a=i}^{n} \frac{1}{a} \\ = \frac{1}{i}+\frac{1}{i+1}+\frac{1}{i+2}+...+\frac{1}{n} $$
It's easy to understand that the revenue for participant $i$ comes from all the people after them (including: themselves, the next person, ..., until the last person $n$), which is the sum of contributions from all these people.

For a participant with $i=5$, the return at $n=12$ in the system is the area of the red part, which is $\approx 102\%$. For any $i$, the return reaches approximately 100% at around $n\approx2.7i$, breaking even.
Plot[{1/Floor[a],
1/Floor[a]*HeavisideTheta[12 - a]*HeavisideTheta[a - 5]}, {a, 1,
15}, PlotRange -> {Full, Full}, Filling -> Axis,
AxesLabel -> {i, "rev from i"}]
$$ \frac{\sum^n_{i=1} \sum^n_{a=i} \frac{1}{a}}{n}=\frac{n}{n} = 100\% $$
Sum[Sum[1/a, {a, i, n}], {i, 1, n}]/n
All the money from the participants is returned to the hands of the participants.
According to basic calculus principles, when the number of participants $\rightarrow \infty$, the long-term return for any participant is $\infty$, regardless of the entry order. Unlike financial markets where every second counts.
$$ R(i,\infty) = \sum_{a=i}^{\infty} \frac{1}{a} \equiv \infty $$
Assume the price of an entry ticket, i.e., the price of 1 point on the number line, is $\delta x \rightarrow 0$.
The participant has a unique ordinal identifier $i \in [1,\infty)$
At some point in the future, the system develops to a maximum identifier of $n \in [1,\infty) , n>i$